Chapter 13- Motion and Time- Extra MCQs (Solved Worksheet)
1. If a student walks around a circular track and returns to the starting point, what is their displacement?
a) Equal to the circumference of the track
b) Zero
c) Depends on the radius of the track
d) Half the circumference of the track
Answer- b) Zero
Explanation- Displacement is the straight-line distance between the start and end points. In this case, the student ends where they started, so the displacement is zero.
2. Which unit is not used to measure speed?
a) m/s
b) km/h
c) m/min
d) kg/m
Answer- d) kg/m
Explanation- Speed is measured in units of distance per time, such as m/s, km/h, or m/min. Kg/m is not a unit of speed but rather implies a unit of mass per unit length.
3. What kind of motion is exhibited by a pendulum?
a) Rectilinear
b) Circular
c) Periodic
d) Random
Answer- c) Periodic
Explanation- A pendulum exhibits periodic or oscillatory motion, as it moves back and forth in a regular pattern.
4. If a car travels 100 km in 2 hours, its average speed is-
a) 50 km/h
b) 200 km/h
c) 2 km/h
d) 100 km/h
Answer- a) 50 km/h
Explanation- Average speed is calculated as total distance covered divided by total time taken. Here, it’s 100 km / 2 hours = 50 km/h.
5. Which of these is a difference between distance and displacement?
a) Distance can be zero, but displacement cannot.
b) Displacement can be zero, but distance cannot.
c) Distance is measured in km, displacement in m.
d) There’s no difference between the two.
Answer- b) Displacement can be zero, but distance cannot.
Explanation- Displacement can be zero if the start and end points are the same, whereas distance is the total path length travelled and cannot be zero if movement has occurred.
6. What does an odometer measure in a vehicle?
a) Instantaneous speed
b) Average speed
c) Distance travelled
d) Fuel efficiency
Answer- c) Distance travelled
Explanation- An odometer is used to measure the total distance travelled by a vehicle, not its speed or fuel efficiency.
7. What characterises non-uniform motion?
a) Constant speed
b) Changing speed
c) Constant direction
d) Movement in a straight line
Answer- b) Changing speed
Explanation- Non-uniform motion occurs when the speed of an object changes over time due to factors like acceleration or deceleration.
8. Which example best represents uniform motion?
a) A car accelerating on a highway
b) A train moving at a steady speed on a straight track
c) A basketball player running on a court
d) A bird flying in varying directions
Answer- b) A train moving at a steady speed on a straight track
Explanation- Uniform motion is observed when an object moves at a constant speed, such as a train moving at a steady speed on a straight track.
9. How was time estimated in the past using shadows?
a) By the colour of the shadows
b) By the length and direction of shadows
c) By the number of shadows
d) By the movement of shadows per hour
Answer- b) By the length and direction of shadows
Explanation- Before the invention of clocks, people used the changing length and direction of shadows throughout the day to estimate time.
10. What does one oscillation of a pendulum include?
a) Movement in one direction only
b) A full movement to one side, then to the other, and back again
c) Half a swing from the mean position
d) Multiple swings back and forth
Answer- b) A full movement to one side, then to the other, and back again
Explanation- One oscillation of a pendulum is a complete movement from its starting point to one side, then to the other, and back to the starting point.
11. What is the time period of a pendulum?
a) The time it takes for multiple oscillations
b) The time it takes to complete one oscillation
c) The duration of its swing in one direction
d) The time it takes to come to a stop
Answer- b) The time it takes to complete one oscillation
Explanation- The time period of a pendulum is the duration it takes to complete one full oscillation.
12. Which of the following is an example of natural time measurement?
a) Stopwatch
b) Sundial
c) Sunrise to sunrise for a day
d) Mechanical clock
Answer- c) Sunrise to sunrise for a day
Explanation- In natural time measurement, a day was defined by the time from one sunrise to the next, relying on the Earth’s rotation
13. How many seconds are there in one hour?
a) 360
b) 3600
c) 60
d) 600
Answer- b) 3600
Explanation- There are 60 seconds in a minute and 60 minutes in an hour, so 60 x 60 = 3600 seconds.
14. What is the basic unit of speed?
a) Kilometre per hour
b) Metre per minute
c) Metre per second
d) Second per metre
Answer- c) Metre per second
Explanation- Speed is distance over time; hence the basic unit of speed is metre per second (m/s).
15. If a healthy adult’s heart beats about 72 times per minute, how many beats are there in 10 seconds?
a) 7.2
b) 12
c) 720
d) 120
Answer- b) 12
Explanation- 72 beats per minute equates to 72/60 = 1.2 beats per second, so in 10 seconds, it would be 12 beats.
16. What type of graph is best used for showing trends over time?
a) Bar Graph
b) Pie Chart
c) Line Graph
d) Scatter Plot
Answer- c) Line Graph
Explanation- Line graphs are effective for displaying trends over time, as they connect data points and show a pattern or trend.
17. A microsecond is one millionth of a second. What is a nanosecond?
a) One hundredth of a second
b) One thousandth of a second
c) One millionth of a second
d) One billionth of a second
Answer- d) One billionth of a second
Explanation- A nanosecond is one billionth (1/1,000,000,000) of a second.
18. In a bar graph, what does the height or length of a bar represent?
a) Time interval
b) Proportion of the whole
c) Quantity or amount
d) Speed of an object
Answer- c) Quantity or amount
Explanation- In a bar graph, the length or height of each bar signifies the quantity or amount of what is being measured.
19. What is the purpose of using a pie chart?
a) To show quantities over time
b) To display proportions of a whole
c) To compare different speeds
d) To measure large time intervals
Answer- b) To display proportions of a whole
Explanation- Pie charts are used to show how a whole is divided into different proportions or parts.
20. Which timekeeping method was used before clocks, based on the sun’s position?
a) Water clocks
b) Observation of shadows
c) Sundials
d) Hourglasses
Answer- b) Observation of shadows
Explanation- Before clocks, people estimated time by observing the length and direction of shadows created by the sun’s position.
21. What does a horizontal line on a distance-time graph indicate?
a) Acceleration
b) Deceleration
c) Constant speed
d) Stationary object
Answer- d) Stationary object
Explanation- A horizontal line on a distance-time graph means no distance is being covered over time, indicating the object is stationary.
22. On a distance-time graph, what does a steeper line represent?
a) Slower speed
b) Higher speed
c) Uniform speed
d) No movement
Answer- b) Higher speed
Explanation- The slope of the line on a distance-time graph represents the speed of the object. A steeper slope indicates a higher speed.
23. What does a straight line on a distance-time graph suggest about the motion of the object?
a) The object is accelerating
b) The object is decelerating
c) The object is moving at a constant speed
d) The object is stationary
Answer- c) The object is moving at a constant speed
Explanation- A straight line on a distance-time graph indicates uniform motion, where the object is moving at a constant speed.
24. If a car moves 1 km every minute, how would its motion be represented on a distance-time graph?
a) A curved line sloping upwards
b) A horizontal line
c) A straight line sloping upwards
d) A straight line sloping downwards
Answer- c) A straight line sloping upwards
Explanation- Since the car is moving 1 km every minute consistently, it indicates constant speed. This is represented by a straight line sloping upwards.
25. In an experiment with a pendulum, if the total time for 10 oscillations is 20 seconds, what is the average time period for one oscillation?
a) 2 seconds
b) 10 seconds
c) 0.5 seconds
d) 20 seconds
Answer- a) 2 seconds
Explanation- The average time period for one oscillation is calculated by dividing the total time by the number of oscillations, which is 20 seconds / 10 oscillations = 2 seconds.
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